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Last Update: 04/27/2025 05:03 PM
Current Deck: LA 2
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Commit #329284
Wie sieht SNF(B(p)) aus?
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Commit #329284
Sei \(p\in K[X] \) normiert vom Grad \(\geq n\).
Dann gilt SNF(B(p)=\(\begin{pmatrix} c_1 \\ & \ddots\\ & & 1 \\ & & & p \end{pmatrix}\in K[X]n,n\)
Dann gilt SNF(B(p)=\(\begin{pmatrix} c_1 \\ & \ddots\\ & & 1 \\ & & & p \end{pmatrix}\in K[X]n,n\)